Question

If the Vertices Of a triangle are (sqrt7 + i sqrt3) , i(sqrt7 + i sqrt3) and sqrt7 + isqrt3 + i(sqrt7 + isqrt3) then the area of Triangle is?

Answer 1

@mukushla

Answer 2

@satellite73

Answer 3

5

Answer 4

yes

Answer 5

i too got it...

Answer 6

thxxxx.....)))

Answer 7

Two sides considered in 3D will be
\[
\text{AB}=\left\{-\sqrt{3}-\sqrt{7},\sqrt{7}-\sqrt{3},0\right\}\\
\text{AC}=\left\{-\sqrt{3},\sqrt{7},0\right\}\\
AB \times AC=\{0,0,10\}\\
Area =\frac 1 2\left | AB \times AC\right|=\frac 1 2 10=5

\]

Answer 8

yw