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OpenStudy (anonymous):
If h(t) represents the height of an object above ground level at time t and h(t) is given by h(t)=-16t2+11t+1 find the height of the object at the time when the speed is zero.
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OpenStudy (anonymous):
\[v(t)=\frac{dh}{dt}\]
Parth (parthkohli):
@jjones144 Did you understand?
OpenStudy (anonymous):
take the derivative of h(t) and set up the equation \[v(t)=0\]
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