Question

Find the x-, y, and z-intercepts for the equation.
2x - 6y - 3z = 12

Answer 1

for x intercept, y and z are 0

Answer 2

2x - 6y - 3z = 12

To find the x-intercept, take y and z as 0.
2x - 0 - 0 = 12
2x = 12
x = 12/2 = 6
To find the y-intercept, take x and z as 0.
0 - 6y - 0 = 12
-6y = 12
-12 = 6y
-12/6 = -2 = y
To find the z-intercept, take y and x as 0.
0 + 0 - 3z = 12
-12 = 3z
-12/3 = - 4 = z

Answer 3

Thanks Guys :)