Question

Please find the laplace transform of this function?
L(t)

Answer 1

you want the laplace using the definition?\[\mathcal L\{t\}=\int_0^\infty te^{-st}dt\]

Answer 2

integrate by parts

Answer 3

\[u=t\]\[dv=e^{-st}\]\[\mathcal L\{t\}=\int_0^\infty te^{-st}dt=-\left.\frac1ste^{-st}\right|_0^\infty-(-\frac1s)\int_0^\infty e^{-st}dt\]\[=-\frac1s\lim_{t\to\infty}\frac t{e^{st}}-\left.\frac1{s^2}e^{-st}\right|_0^\infty=\frac1{s^2}\]

Answer 4

did you have a question about this?

Answer 5

Thanks

Answer 6

Please could you make it a little more explicit?