Question

j(x) =

k cos(x), x ≤ 0
11ex − k, 0 < x

find K

Answer 1

\[j(x)= Kcos(x) \] at x<or equal 0

Answer 2

given that it is continuous ?

Answer 3

\[f(x) = \left\{\begin{array}{rcc}
k\cos(x) & \text{if} & x\leq0 \\
11e^x-k& \text{if} & x> 0
\end{array}
\right.\]
??

Answer 4

this is easier than you may think
replace \(x\) by zero in both expressions, set them equal and solve for \(k\)