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If F(theta)=tan theta=3, find F(theta+pi)
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hint: \[F(\theta + \pi) = \tan(\theta + \pi)\] does that help?
not really
okay...you have \[\tan \theta = 3\] do you know how to solve for theta?
no thats what i need to know
take arctangent of 3..what do you get?
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-0.143
is that wrong
please help me my teacher didnt go over this part
How did -0.143 come about?
i put it in my calculator
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now im really confused
\[\tan ^{-1} (3) = 1.249\] ..?
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