Question

|f(x)|=4-(x+1)^2
Please help

Answer 1

what do have to with this??

Answer 2

graph it

Answer 3

do u have to graph \(f(x)=4-(x+1)^2\), or given this graph \(y=|f(x)|\)??

Answer 4

yea the second one i think it just says abs value f(x) with that as f(x)

Answer 5

OK. f(x) is a parabola
\[ \large y=4-(x+1)^2 \]
\[ \large y-4=-(x+1)^2 \]
with vertex at (-1,4) that opens downwards (due to the sign).

Answer 6

something like this

Answer 7

wait it goes below the y axis?

Answer 8

now finally \(y=|f(x)|\).
the absolute value "folds" the plane at the x-axis. and everything ends up laying on the upper half of the plane