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how do you solve 3x^2y-11xy+8y by factoring?
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start by factoring out the (y\) which is common in all three terms that will give you \(y(3x^2-11x+8)\) then see if you can factor the stuff inside the parenetheses
i guess you just have to grind it til you find it it will look like \((3x+a)(x+b)\)
i think \((x-1)(3x-8)\) will work, multiply out and see if you get what you started with
wouldn't (x-1) (3x-8) be the answer?
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