Question

\[\int {4x - 6\sqrt[3]{x^2} dx}\]

Answer 1

And I get\[2x^2 - {18 \over 5}x^{5 \over 3} \]

Answer 2

derive that and see if you get the question

Answer 3

Yes, I do... so that's right

Answer 4

i mean...try differentiating your answer...if it results to be the same as your question..you're right

Answer 5

right

Answer 6

\[{d \over dx} 2x^2 - {18 \over 5}x^{5 \over 3} = 4x - 6x^{2 \over 3} \]

Answer 7

Yep!