Question

Ricardo Gutierrez has a box of coins that he uses when playing poker with friends. The box contains 28 coins, consisting of pennies, dimes, and quarters. The number of pennies equal to the number of dimes, and the total value is $2.34. How many of each denomination of coins does he have?

Answer 1

lets call the number of pennies \(x\)
then the number of dimes is also \(x\)
since there are 28 coins, the number of quarters must therefore be \(28-2x\)

total amount of money in pennies is \(234\) and that must be \(x+10x+25(28-2x)\) so solve
\[x+10x+25(28-2x)=234\] for \(x\)

Answer 2

-39x+466 ?

Answer 3

????

Answer 4

that is correct left side,
so -39x+466=0
then x= 466/39 = ??

Answer 5

11.?

Answer 6

0? @hartnn?

Answer 7

11.949
or 12 approximately.

Answer 8

So there were 11.949 quarters and 234 pennies and dimes?

Answer 9

@hartnn ?

Answer 10

no,the dimes and pennies are of same number = 12

Answer 11

and the quarters are?

Answer 12

28-2x=28-2*12=28-24=4

Answer 13

So 11.949 penies and dimes and 4 quarters?

Answer 14

yes,to be exact.

Answer 15

Find a value for x so that 4/10=-2/x?

Answer 16

will it be x=5?

Answer 17

u forgot negative sign, x=-5

Answer 18

oh, i sure did forget the negatvie sign lol, thanks

Answer 19

What is the converse and inverse of the statement? If charles wrote a sonata, then snoppy did not dance a jig.