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3/2x-4=16 How do i solve for x ?
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multiply both sides by 2x-4
\[(2x-4)*\frac{ 3 }{ 2x-4 }=16*(2x-4)\]
now you'll have \[3=16(2x-4)=32x-64\]
can you solve for x now?
|dw:1346943903255:dw| thats what it was supposed to say sorry
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okay....multiply every term by 2x
\[2x*\frac{ 3 }{ 2x }-4*2x=16*2x\]
ok thanks
:)
3-8x=32x
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