Question

Solve: x2 – 16x + 15 = 0

Answer 1

Compare your quadratic equation with \(ax^2+bx+c=0\)
find a,b,c
then the two rots of x are:
\(\frac{-b \pm \sqrt{b^2-4ac}}{2a}\)

Answer 2

x^2 or 2X?

Answer 3

(x-15)(x-1)
Is more easy to see, 2 numbers that a.b = 15 and plus = -16
(-15)(-1) = 15
-15-1 = -16