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Find the perimeter and area of a right triangle if the shortest side is 12 cm and the longest side is 20 cm. Include correct units with each part of your solution.
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area is just \[\frac {bh}2\] base is 12 and height is 20
Do i multiply?
yes
240?
now divide by 2
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120
that's your area now
to solve for perimeter... \[P = b + h + \sqrt{b^2 + h^2}\]
Help?
again... b is 12 and h is 20
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just substitute
P=b+h+b^2+h^2 12+16+20=48 cm. Sides are 12,16,20
wait...im checking....
how did you get 16?
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