Question

Factor: s⁶-27t⁹

using difference of cubes please

Answer 1

hint \[\huge s^6 - 27t^9 \implies (s^2)^3 - (3t^3)^3\]
does that help?

Answer 2

formula for difference of cubes is \[\huge a^3 - b^3 = (a-b)(a^2 + ab + b^2)\]