Question

Find the inverses of f(x) = 1/8 (x-3) and g(x) = x^3 then find:

f^-1(g^-1(1))
g^-1(f^-1(-3))
f^-1(f^-1(6))
g^-1(g^-1(-4))
f(g)^-1
g^-1(f^-1)

Pre-calculus just gets complicated everyday..

Answer 1

My inverses: \[f^{-1}(x) = 8(x + 3)\]
\[g^{-1} = \sqrt[3]{x}\]

Answer 2

please just help me with the first one and i'll do the rest.