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(3x-5)^2
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write it as \[(3x-5)(3x-5)\]then distribute:\[9x^2-30x+25\]
3x-25
No thor no..
^no you have to expand binomials
me?
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@Thorgod
Oh.
.................. *backs away*
and even if you hadnt expanded and just squared (which is totally wrong) it would be 9x^2+25 not 3x+25 :)
T-T
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@smokes your answer is 9x^2-30x+25 :)
Yummydummy is very vigorous in situations like these..
i am? o.O
thats not my name -.-
:P
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He eats away his competitors.
he???????? O_O
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