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Solve (x/3)^-1
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Using the exponent law.
3/x
1/(x/3) = 3/x
Always remember that : \[\large{a^{-1}=\frac{1}{a^1}}\]
\[\frac{ 3 }{ x}\]
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Hence we get : \[\large{[{\frac{x}{3}}]^{-1}=\frac{3}{x}}\]
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