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5/3d=15/9 please help! soldve the equation. use the domain of rational numbers.
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|dw:1346979085876:dw|
We can cross multiply to find: \[ 5\cdot9=15\cdot3d=45d=45 \]So: \[ d=1 \]Another way would be: \[ \frac{15}{9}=\frac{5\cdot\not3}{3\cdot\not3}=\frac{5}{3} \]So, \(d\) would have to be one.
uhm d=1?
Yep.
ooo got it thanks
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