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Mathematics 10 Online
OpenStudy (anonymous):

3+√3X+1=X

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

but wouldnt it be √3x+1=x-3 and then square them since the 3x+1 is under the radical?

OpenStudy (anonymous):

Oh, so you mean √ ( 3x +1) = x - 3 ?

OpenStudy (anonymous):

exactly

OpenStudy (anonymous):

okay so i dont know how to enter it here but my final answer is x^2-3x+8

OpenStudy (anonymous):

is that correct?

OpenStudy (anonymous):

x² - 9x + 8 = 0

OpenStudy (anonymous):

how u get that?

OpenStudy (anonymous):

it just says find the real solution

OpenStudy (anonymous):

Anyway: 3x + 1 = x² - 6x + 9 x² - 6x - 3x + 9 -1 = 0

OpenStudy (anonymous):

x^2-9x+8=0 right

OpenStudy (anonymous):

yes i can thank you so much 4 ur help!

OpenStudy (anonymous):

Remember to post with parentheses, it'll less confused the helpers :)

OpenStudy (anonymous):

ok i'll keep that in mind!

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