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3+√3X+1=X
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yes
but wouldnt it be √3x+1=x-3 and then square them since the 3x+1 is under the radical?
Oh, so you mean √ ( 3x +1) = x - 3 ?
exactly
okay so i dont know how to enter it here but my final answer is x^2-3x+8
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is that correct?
x² - 9x + 8 = 0
how u get that?
it just says find the real solution
Anyway: 3x + 1 = x² - 6x + 9 x² - 6x - 3x + 9 -1 = 0
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x^2-9x+8=0 right
yes i can thank you so much 4 ur help!
Remember to post with parentheses, it'll less confused the helpers :)
ok i'll keep that in mind!
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