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Factor the difference of two cubes. X^3^n-1
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|dw:1346985791020:dw|
(x^n)^3-(1)^3
Now: HINT a^3-b^3 = (a-b) (a^2 + ab + b^2)
Does it help?
Not really im still confused
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Just use the formula
which formula was the answer?
(x^n)^3-(1)^3 HERE suppose a=x^n and b=1
And use a^3-b^3 = (a-b) (a^2 + ab + b^2)
ok so that is the answr
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?
First try yourself
(x^n-1) (x^2n + x^n +1)
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