Question

Find the smallest angle with sides 2m, 3m, 4m.

Answer 1

The angle opposite to the smallest side is smallest angle in a trianglr

Answer 2

I mean triangle

Answer 3

saura is right.

Answer 4

and we will use cosine for this right?

Answer 5

A greater angle of a triangle is opposite a greater side.

Answer 6

2^2 = 4^2 + 3^2 2(4)(3) (cos x)

Answer 7

I see can someone show me the cosine step, I keep messing up the BEDMAS

Answer 8

Well if you have to find the exact angle. Haven't gotten there yet.

Answer 9

YA use cosine rule if u want to find the exact value of the angle

Answer 10

well can you show that for me, I tried a lot but failed each time. My steps just doesn't help me get the answer.

Answer 11

U want to find the value of smallest angle?

Answer 12

yes. that's what the question asks.

Answer 13

let x be the smallest angle

Answer 14

then,
(2m)^2=(3m)^2+(4m)^2-2*3m*4m*cosx

Answer 15

Now, solve for x

Answer 16

wait why is there an m there?
Regardless, 4m^2 = 9m^2 + 16m^2 - 24m*cosx

Answer 17

did i do that right?

Answer 18

(2m)^2=(3m)^2+(4m)^2-2*3m*4m*cosx
4m^2=9m^2+16m^2-24m^2 cosx

Answer 19

ohhhhh
4m^2 -25m^2 = -24m^2 cosx
-21m^2/-24 = cosx
7/8 = cos x
inverse cos(7/8) = x
28.95 = x

Answer 20

thankss :)

Answer 21

YEP

Answer 22

:)yw