Question

f tanx+sinx=m,tanx-sinx=n show that m^2-n^2=4(mn)^0.5.

Answer 1

whr r u stuck

Answer 2

f tanx+sinx=m,tanx-sinx=n show that m^2-n^2=4(mn)^0.5.

Answer 3

lol, plug in the values of m and n

Answer 4

before plugging in write m^2-n^2 as (m+n)(m-n)
it will be simplified.

Answer 5

m+n=2 tan x
m-n = 2 sin x

Answer 6

so Left side = 4sin x tan x

Answer 7

mn = tan^2 x - sin ^2 x
using (a+b)(a-b)=a^2+b^2

Answer 8

which is sin^2 x tan^x
so \(\sqrt{mn}\)= sin x tan x

Answer 9

which gives u what u wanted.