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Mathematics
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OpenStudy (anonymous):
Rewrite with only sin x and cos x.
cos 2x + sin x
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hartnn (hartnn):
cos 2x=2 cos^2 x-1
OpenStudy (anonymous):
cos 2x= co(x+x)= cos x cos x - sinx sin x
OpenStudy (anonymous):
i think it is 1 +3 sin^2x
OpenStudy (anonymous):
cos 2x= co(x+x)= cos x cos x - sinx sin x
=1- 2 sin^2 x
= 2 cos^2x -1
hartnn (hartnn):
there are 3 different formulas for cos 2x,use any to bring it in the form of sin x and cos x
then there will be 3 equivalent answers.
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OpenStudy (anonymous):
cos2x=2sinxcocsx
2sinxcosx+sinx=sinx(2cosx+1)
OpenStudy (anonymous):
so what would the anserw be?
OpenStudy (anonymous):
1 + 2 sin^2x + sin x
hartnn (hartnn):
if u have choices, list them
else any of the 3 answers are correct
1-2sin^2 x+sin x
OpenStudy (anonymous):
A1 + 3 sin x
B1 + 3 sin2x
C1 - 2 sin^2x + sin x
D1 + 2 sin^2x + sin x
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hartnn (hartnn):
2cos^2x -1+sin x
and
cos^2 x-sin^2x +sin x
hartnn (hartnn):
C matches.
OpenStudy (anonymous):
THANKS SO MUCH
hartnn (hartnn):
welcome :)
OpenStudy (anonymous):
cos^2x-sin^2x+sinx=1-sin^2x-sin^2x+sinx=1-2sin^2x+sinx
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OpenStudy (anonymous):
babydoll u can understant that?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ya ok
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