What is the equation of a circle that passes through point J(6, 4) and has center K (1, -8).

a. (x + 1)2 + (y - 8)2 = 196
b. (x - 1)2 + (y + 8)2 = 169
c. (x + 1)2 + (y - 8)2 = 121
d. (x - 1)2 + (y + 8)2 = 144

Question

What is the equation of a circle that passes through point J(6, 4) and has center K (1, -8).

a.	(x + 1)2 + (y - 8)2 = 196
b.	(x - 1)2 + (y + 8)2 = 169
c.	(x + 1)2 + (y - 8)2 = 121
d.	(x - 1)2 + (y + 8)2 = 144

anonymous · Answer

-What is the equation of the circle?
-What do you use to work out the length KJ (Hint: Pythagoras)?
-What IS KJ?

anonymous · Answer

I dont know :/

anonymous · Answer

Okay- you know pythagoras' theorem?

anonymous · Answer

no

anonymous · Answer

i suck at math

anonymous · Answer

It's REALLY useful, even for everyday things.

anonymous · Answer

Basically, |dw:1347048356964:dw|

anonymous · Answer

|dw:1347048365815:dw| You make squares using the lengths

anonymous · Answer

Now, if the triangle has a right angle here:|dw:1347048415330:dw|

anonymous · Answer

Then A is ALWAYS equal to B+C

anonymous · Answer

What is the area of a square? Length*length.

anonymous · Answer

7?

anonymous · Answer

|dw:1347048473746:dw|$$A=B+C$$so$$p*p=q*q+r*r$$$$p^2=q^2+r^2$$