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16n^2-1=0 n=? solve and check help please
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Hint: Use the difference of squares factoring rule a^2 - b^2 = (a-b)(a+b)
(4n+1)(4n-1)??
good, so 16n^2-1=0 turns into (4n+1)(4n-1) = 0
Now use the zero product property to break up that last equation to get 4n+1 = 0 or 4n-1 = 0
So the answer would be -4/1,4/1
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close, but no
4n+1 = 0 4n =-1 n = -1/4 --------------- 4n -1 = 0 4n = 1 n = 1/4 So the solutions are n = -1/4, n = 1/4
cool thank you that makes sense thanks alot for breaking it down
np
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