Question

A ball is thrown upward with an initial velocity of 96 ft/sec from a height h, in feet, after t seconds is given by (h)t=-16t^2+96t+640. After how long will the ball reach the ground?

Answer 1

solve for t when h(t)=0

Answer 2

there's always the quadratic equation if you dont want to factor it

Answer 3

So through the equation t will be replaced with 0?

Answer 4

0=-16t^2+96t+640

Answer 5

thanks