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Mathematics 19 Online
OpenStudy (anonymous):

derivative of arctan(sinh2x)

OpenStudy (lgbasallote):

first.. do you know the derivative of arctan u?

OpenStudy (anonymous):

du over 1 - u^2

OpenStudy (anonymous):

switch your sign, then you're right :)

OpenStudy (anonymous):

and du is for integration... so it's actually 1 over 1+u^2

OpenStudy (anonymous):

1 - u^2 to u^2 - 1?

OpenStudy (lgbasallote):

1 - u^2 into u^2 + 1

OpenStudy (lgbasallote):

should be + not -

OpenStudy (lgbasallote):

\[y= \arctan u\] \[\tan y = u\] \[\sec^2 y y' = 1\] \[y' = \frac{1}{\sec^2 y}\] \[y' = \frac{1}{u^2 + 1}\] here's some visuals |dw:1347081218296:dw|

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