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If w is the non-real cube root of unity then \[w^{\frac{1}{4}}(w^{\frac{1}{2}}*w^{\frac{1}{6}}*w^{\frac{1}{18}}*w^{\frac{1}{54}})........ infinity\]
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can u find the sum of geometric sequence 1/2,1/6,1/18..... ??
its a/(1-r) = 0.5/(1-1/3)=0.5/(2/3)=3/4 ok?
i got it....thxxx
so w^(1/4)* w^(3/4) = w.
welcome :)
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