Out of 40 students, 14 are taking English and 29 are taking Chem. If 5 students are in both, how many students are in neither class

Question

anonymous · Answer

3

anonymous · Answer

can you show your work so i can understand it? thanks

anonymous · Answer

@Zekarias

anonymous · Answer

So we know, by the principle of Inclusion exclusion:
$$
|A\cup B|=|A|+|B|-|A\cap B|
$$So, we wish to find the remaining of the fourty such students, we say:
$$
|A\cup B|=14+29-5=38
$$So, the total number of students is 40, and the students taking at least one of Chem OR English is 38. So we must have 2 students not in a class.

anonymous · Answer

First find the number students who are taking both subject : 14+29-5 = 37
Then subtract it from the total : 40-37 = 3

anonymous · Answer

Lolwolf what is the value for 14+29-5

anonymous · Answer

You tell me. 29-5=24
And 24+14=38.

anonymous · Answer

right, thanks

anonymous · Answer

thanks guys!!!