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A set has 9 elements. How many subsets have at most 3 elements?
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The empty set, a set that contains only one term.. so 10 so far..
and then a set that contains 2 terms, so 8 more, 18 so far
C(9,3)+C(9,2)+C(9,1)+1(for the empty set)?
yea basically
The total number of ways we can pick a subset of a set, with a subset length \(|P|\) and a set length of \(|S|\) is: \[ \binom{|S|}{|P|} \]So, we get: \[ \binom{9}{0}+\binom{9}{1}+\binom{9}{2}+\binom{9}{3} \]
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