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What is the general form of the equation of the line shown? x - 2y - 3 = 0 2x - y + 3 = 0 2x - y - 3 = 0
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Simplify this using point-slope form.\[y - y_1 = m(x - x_1)\]
Take any two points from the graph and then tell me.
All right, just take (2,1) and (-1,-1). What do you get for the slope?
would It be #2?
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\[slope = \frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]
Yes
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