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An arrow is shot vertically upward and then 2.00s later passes the top of a tree 40.0m high. How much longer will the arrow travel upward? and how high will it go?
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You have to figure out the initial velocity. \[40=\frac{ 1 }{ 2} g t ^{2} +v _{o}t\]
thank you so much, I final got the same answer as my professor
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