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Let F(x)=3x^2-5 and g(x)=3x+6. Find the following. (f-g)(-3)=
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\[3x^2 - 5 - (3x + 6)\]\[\implies 3x^2 - 5 + 3x - 6\]
Now plug in x = -3
\[\implies 3(-3)^2 - 5 + 3(-3) - 6\]continue
7?
Dude come on, can you not add?
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3*9 - 5 - 9 - 6
25?
27 - 5 - 9 - 6
THAT is 7
huh?
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right
I typed 7 in the box it is wrong..
so now what?
Ok let's check our work..
i checked it it is right
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wait so did you get the answer?
yes
i deserve a metal
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