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-2y^(2) x -5y would it come out as 10y^(2) or ^(3) or something else?
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Yeah, ^(3)
-2*-5 = 10 and y^2*y = y^3 so 10y^3
\[-2y^2 \times -5y\]\[\implies -2 \times y \times y \times -5 \times y\]\[\implies (-2 \times -5) \times (y \times y \times y)\]
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