Question

Compute a·(b x c), Where a=i-2j+k, b=2i+j+k and c=3i-j+2k.
I got 4 as an answer, I wanted to make sure that was right.

Answer 1

what did you get for bxc?

Answer 2

I got (3,1,-5)

Answer 3

I got 0 as the answer. You forgot that the j component has to be negative, so it would be (3,-1,-5)

Answer 4

1 -2 1
3 1 -5
--------
3 -2 -5 = -4

Answer 5

4-3 = 1, negate to -1 .... yeah

Answer 6

so it is 0?

Answer 7

yes, its zero :)

Answer 8

Okay, thanks so much!