Question

Solve the equation in quadratic formula!
2x^2-9x-2=0

Answer 1

i got 9\[9\pm \sqrt{65}/4\]

Answer 2

Then \[x = \frac{ -b \pm \sqrt{b ^{2} - 4ac } }{2a}\]

Where a = 2 b = -9 c = 2

Answer 3

i know how to do that
i just got confused at the end

Answer 4

\[x = \frac{ 9\pm \sqrt{97}}{4}\]

Answer 5

c = -2 .. sorry my mistake..!

Answer 6

yeah it should be \[\sqrt{65}\] not\[\sqrt{97}\]

Answer 7

its \[\sqrt{97}\]
since b^2 - 4ac = (-9^2) - (4x 2 x -2) = 81 - (-16) = 97

Answer 8

ur right i subtracted instead of add. thank you

Answer 9

Ur Welcome..!! (:

Answer 10

So you got the answer?

Answer 11

yes