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If x≠-1,x≠1 or x≠3, then what is (x^2-x)/(2x-6)*(x^2-2x-3)/(x^2-1) ?
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can u factor x^2-2x-3 ?
yeah (x+1)(x-3)
so, x^2-x=x(x-1) x^2-1=(x+1)(x-1) now just substitute these factors and see what cancels.
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