Question

An arrow is shot vertically upward and then 2.00s later passes the top of a tree 40.0m high. How much longer will the arrow travel upward? and how high will it go?

Answer 1

use the kinematics equations

Answer 2

treat the initial position as zero, the final position as 40.0 m, the beginning velocity as v initial, the acceleration as -9.8 and the change in time as (t final- t initial) which is (2.0-0)

Answer 3

does that help?