Question

Can someone help me with two problems about equations? Two of my answers were wrong!

Multiply or divide as indicated.

x^-8 times x^-2

I think that it could be x^10...


Multiply or divide as indicated. Simplify your answer, if possible.

b^3 times b^-3

I think that the answer is b^6..

Answer 1

nopes, both incorrect.

Answer 2

\(\huge a^x*a^y=a^{x+y}\)

Answer 3

x^a*x^b = x^(a+b)

Answer 4

so \(\huge x^{-8}*x^{-2}=x^{-8-2}=??\)

Answer 5

hint: b^3*b^(-3) = b^3/b^3

Answer 6

I'm used to interpreting negative exponents as inverses of the base times the index.

Answer 7

ok...

Answer 8

@hartnn x^-6??

Answer 9

what is -8-2?

Answer 10

actually -8-2 = -10
so , it will be \(x^{-10}\)
ok?

Answer 11

@zzr0ck3r b^6?

Answer 12

ok

Answer 13

what is a/a = b/b= 3/3 = d/d = smiley/smiley = b^3/b^3 = ?

Answer 14

b^3

Answer 15

a/a = b^3?

Answer 16

what is 2/2?

Answer 17

1

Answer 18

what is 76584/76584?

Answer 19

It's 1...

Answer 20

what is a/a?

Answer 21

a

Answer 22

anything devided by itself is 1

Answer 23

so what is b^3/b^3 ?

Answer 24

1!!!

Answer 25

correct

Answer 26

note: b^3*b^(-3) = b^(3+(-3)) = b^(3-3) = b^0 = 1

Answer 27

x^-10