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how: kx+8=5x equals 8/5-k? -4(2x+1)-(x-2)=-11 equals 1?
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\[kx + 8 = 5x\] subtract kx from both sides \[\implies 8 = 5x - kx\] factor out x.. \[\implies 8 = x(5-k)\] then, lastly, dividie both sides by 5-k does that help?
yes, what about the second one??
just expand it and distribute \[\implies -8x - 4 - x + 2 = -11\] solve for x
thanks :) , second one i mistakenly had -2 instead of +2 that's why i get -7/9 as an answer
i see
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