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\[(x ^{2}-4)\rightarrow (x+2)(x-2)\] does that further you along?
yes
did u factor the difference of cubes??
no
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do u know how?
(x-2)(x-2)(x-2) =x^3-8 ?
no way
\[ \large x^3-8=x^3-2^3=(x-2)(x^2+2x+2^2) \]
the general formula is \[ \large a^3-b^3=(a-b)(a^2+ab+b^2) \]
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now u have everything factored. just plug in and simplify
it is easy. tell me what u get
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