Question

Derive d(t)=4+2cos6(t-3) for both the velocity and acceleration functions.

Answer 1

I solved them but i dont know if i am correct or not. I got 2cos6 as the velocity and 0 as the acceleration. Is this correct?

Answer 2

differentiate to find v:
-sin 6(t-3) * 6 * 2
= -12 sin 6(t-3)

Answer 3

i've assumed you mean