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Lim (x+1)^2-1/x ? x>>>0
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did u mean: (x+1)^2 - (1/x) ?
no i mean divided by x
oh the whole thing?
yes
((x+1)^2-1)/x
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Ok, (x^2+2x+1-1)/x = (x^2+2x)/x=x(x+2)/x=x+2
Now you can simply plug in x=0, and get the limit: 0+2=2
lim(x+1)^2 -1/x
where x>>>1
|dw:1347294158590:dw|
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