Let t be time in seconds and let r(t) be the RATE (not the total amount), in gallons per second, that water enters a reservoir:

r(t)=700−40t
For 0t30, when does the reservoir have the most water? (Hint: The net area bounded by the rate graph represents the displacement in water on the given interval.)

Question

Let t be time in seconds and let r(t) be the RATE (not the total amount), in gallons per second, that water enters a reservoir: 
  
      r(t)=700−40t 
For 0t30, when does the reservoir have the most water? (Hint: The net area bounded by the rate graph represents the displacement in water on the given interval.)

anonymous · Answer

u know how to graph it. it s a straight line with a negative slope

anonymous · Answer

yeah i know how to graph it, but i dont know how to find when it has the most water

anonymous · Answer

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max water is when rate reaches zero

thats the TOTAL area

anonymous · Answer

how do i figure that out? i still dont know