Let $ a, b, c 0 $, show that
$$ \sqrt{\frac{11a}{5a+6b}}+\sqrt{\frac{11b}{5b+6c}}+\sqrt{\frac{11c}{5c+6a}} \leq 3. $$
from http://math.stackexchange.com/questions/193568/inequality-sqrt-frac11a5a6b-sqrt-frac11b5b6c-sqrt-frac11c

Question

Let $ a, b, c > 0 $, show that
$$ \sqrt{\frac{11a}{5a+6b}}+\sqrt{\frac{11b}{5b+6c}}+\sqrt{\frac{11c}{5c+6a}} \leq 3. $$
from http://math.stackexchange.com/questions/193568/inequality-sqrt-frac11a5a6b-sqrt-frac11b5b6c-sqrt-frac11c

turingtest · Answer

yeah this is gonna be a pain with LaTeX down :S

experimentx · Answer

isn't latex working for you? this Q seems fairly complicated ... I've been stalking for more than 2 hrs.

turingtest · Answer

no, GoDaddy isn't supporting mathjax right now, there is an announcement in the yellow bar on the home page, Why, is it working for you o.O ?

experimentx · Answer

I'm using chrome ... what server does MathJax uses to parse latex?

turingtest · Answer

not sure, not that tech savvy...
but I have chrome as well. do you see the TeX normally or not?

experimentx · Answer

I see it normally ...

anonymous · Answer

Let us suppose a is the largest number out of the the three...... then |dw:1347343904345:dw| will have the largest value.... So now, this value is maximum when a approaches infinity So,|dw:1347343979969:dw|