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Mathematics 19 Online
OpenStudy (anonymous):

Differentiate the function.

OpenStudy (anonymous):

\[f(x)= \frac{ x }{ x + c/x }\]

OpenStudy (lgbasallote):

quotient rule

OpenStudy (anonymous):

\[\frac{ (x+c/x)(1)-(x)(1+ ??)}{ (x+x/x)^2 }\]

OpenStudy (anonymous):

c/x would be ?

OpenStudy (lgbasallote):

\[\large \frac{d}{dx}cx \implies cx^{-1} \implies -cx^{-1 - 1} \implies -cx^{-2} \implies -\frac c{x^2}\] got it?

OpenStudy (lgbasallote):

that's d/dx (c/x)

OpenStudy (anonymous):

yep thankS!

OpenStudy (lgbasallote):

welcome

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