Coluld you please show me how to sold these problems?

Question

anonymous · Answer

attachment

anonymous · Answer

where are you confused?

anonymous · Answer

I just dont even know were to start :/ i know i have to factor but were do i go next?

anonymous · Answer

well we're trying to solve for one of the variables here right?  so the equation would be set equal to zero.

anonymous · Answer

Lets take a look at the first problem in that list.  Is there away you could simplify it?  If so, what would that be?

anonymous · Answer

Well it would abvousely be $$\frac{ 3x-10 }{ 9 }$$ then what would i do

anonymous · Answer

we would set this equal to zero and then begin to get 'x' by itself.

anonymous · Answer

Yes, i kind of stepped ahead there.

anonymous · Answer

Sorry about that

anonymous · Answer

It's okay.
$$\huge {3x - 10 \over 9} = 0$$
$$\huge \not 9 * {3x - 10 \over \not 9} = 0 * 9$$
$$\huge 3x -10 = 0$$

Does this help so far??  Can you finish the rest?

anonymous · Answer

Isnt that soppost to be all over 9?

anonymous · Answer

well on the LHS, multiplying by 9, divides the 9 out from the bottom.  and then 0*9 is =0.  Remember, what you do on one side of the equation you must do on the other.  Since we are dividing by 9, the only way to "move it over" is to multiply by it.

Similarly, when wanting to move the -10 over, you'll add it to both sides.  Does that make sense?