Question

2(theta)cos(THETA)+THETA=0

Answer 1

factor out a theta
\[\rightarrow \theta (2\cos(\theta) +1) = 0\]

Answer 2

how would you solve it? even after factoring out? littile confused?

Answer 3

solve by setting each factor equal to 0
\[\theta = 0\]
\[2 \cos \theta +1 = 0\]

Answer 4

2cosθ+1=0
=1+sin2θ

Answer 5

^?

Answer 6

2cosθ+1=0
2cosθ=-1
cosθ=-1/2