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How many multiples of 3 are there between 1167 and 2048 inclusive?
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I have started off with Tn = 1167 + (n-1)3 = 1167 + 3n-3
im stuck after that
Notice how 2048 isn't a multiple of 3, but 2046 is since 2046/3 = 682 So 1167/3 = 389 and 2046/3 = 682 which means 1167 = 3*389 and 2046 = 3*682
Your first term is 1167 and last term is 2048 with common difference 3
So the sequence 1167, 1170, ..., 2046 can be written as 3*389, 3*390, ..., 3*682
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So you need to count how many numbers there are from 389 to 682
293?
close, 294
oh yeah
thanks
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