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Find the domain of the function The function inside
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\[y=\sqrt{x-2}\times \sqrt{x+2}\]
all R EXCEPT 2 and -2
no
it cant be less than -2 for the second equation and it cant be less then 2 for the first, since -2 , 2 the 2 wins out, thus it cant be less than 2
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which part of these are you having a problem with? we cant devide by 0 and we cant take square roots of negative numbers, so make sure you are shecking for these things. I dont know if you are doing logs yes but we cant take logs of negative numbers also. these are the main things we need to look for when solving domain.
I understand it, but if between roots is + How to solve in this case?
Hint: \(\sqrt{ab} = \sqrt{a} * \sqrt{b}\).
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